If f x is a polynomial function satisfying
Web30 okt. 2024 · If f (x) is a polynomial function of x, satisfying f (x). f (y) = f (x) + f (y) + f (xy) – 2 such that f (1) = 2 and f (2) = 5, then find the value of f (6) + 2009. functions jee jee mains 1 Answer +1 vote answered Oct 30, 2024 by Raghab (50.8k points) selected Nov 4, 2024 by faiz Best answer Given f (x) f (y) = f (x) + f (y) + f (xy) – 2 WebIf f (x) is a polynomial in x (> 0) satisfying the equation f (x) + f (x 1 ) = f (x) f (x 1 ) and f (2) = 9, then f (3) =
If f x is a polynomial function satisfying
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Web6 mrt. 2024 · Given f (x) is a polynomial function of x, satisfying f (x) ⋅ f (y) = f (x) + f (y) + f (xy) − 2 and that f (2) = 5. Then f (3) is equal to? A) 10 B) 24 C) 15 D) none Calculus Introduction to Integration Integration: the Area Problem 1 Answer Cesareo R. Mar 6, 2024 option d) Explanation: f (1)f (3) = f (1) +f (3) + f (3) −2 then Web6 mrt. 2024 · Given f (x) is a polynomial function of x, satisfying f (x) ⋅ f (y) = f (x) + f (y) + f (xy) − 2 and that f (2) = 5. Then f (3) is equal to? A) 10 B) 24 C) 15 D) none. Calculus …
Web30 okt. 2024 · If f(x) is a polynomial function of x, satisfying f(x). f(y) = f(x) + f(y) + f(xy) – 2 such that f(1) = 2 and f(2) = 5, asked Oct 30, 2024 in Sets, relations and functions by SumanMandal ( 54.9k points) WebExample 2: Verify Rolle’s theorem for the function f(x) = x 2 - 4 x + 3 on the interval [1 , 3], and then find the values of x = c such that f '(c) = 0. Solution: f is a polynomial function, therefore is continuous on the interval [1, 3] and is also differentiable on the interval (1, 3). Now, f(1) = f(3) = 0 and thus function f satisfies all the three conditions of Rolle's theorem.
Web27 mrt. 2024 · If f(x) is a polynomial function satisfying f(x). f(1/x) = f(x) + f(1/x) ∀ x ∈ R – {0} and f(2) = 9, then find f (3). function; jee; jee mains; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered Mar 27, 2024 … WebSince, f(x) is polynomial function, so (f(x)−1) and f(x1)−1 are reciprocals of each other. Also, x and x1 are reciprocals of each other. Thus, Eq. (iii) can hold only when. f(x)−1=±x …
WebIf f (x) is a polynomial function satisfying the condition f (x) × f (1x) = f (x) + f (1x) and f (2) = 9 then. Class 11. >> Applied Mathematics. >> Functions. >> Graphs of functions. …
Web25 jun. 2024 · Suppose `f` is a real function satisfying `f(x+f(x))=4f(x)a n df(1)=4.` Then the value of `f(21)` is `16` `21` `64` `105` asked Jan 21, 2024 in Mathematics by EashtaBasu ( 97.0k points) class-12 inspiring hopeWeb9 jan. 2015 · Let f be an integer polynomial with f ( x) f ( 1 / x) = f ( x) + f ( 1 / x). There are four solutions, f = 0, f = 2, and f = 1 ± x n. Clearly f = 0 is a solution. As in the question, … jet express to put in bay scheduleWebAnswer: The function satisfying the equation f(x)* f(1/x) = f(x) + f(1/x) takes the form f(x)=1+x^n and since it is given that f(4)=65, we obtain n=3 This turns the ... jet fashion onlineWebIf f x is a polynomial satisfying the relation f x + f 2 x =5 x 2 18 then f 11 is equal toA. 1B. 2C. 3D. Cannot be found since degree of f x is not given. Login. Study Materials. NCERT Solutions. ... If f: R → R is a function satisfying the functional relation f (2 x + 3) + f ... inspiring human belief in a healthier worldWebIf fx be a polynomial function satisfying fx·f1/x=fx+f1/x and f4=65. Then find f6. jet fans for car park ventilation calculationWeb14 apr. 2024 · If \( f \) is a polynomial function satisfying \( f(x) \cdot f\left(\frac{1}{x}\right)=f(x)+f\left(\frac{1}{x}\right) \) and \( f(2)=-3 \), then draw graph o... inspiring hope church hamilton ohioWebSolving polynomials We solve polynomials algebraically in order to determine the roots - where a curve cuts the \ (x\)-axis. A root of a polynomial function, \ (f (x)\), is a value... jet fan thrust equation