If tana 5/12 then sin a + cos a .sec a
Web1 jun. 2024 · If tan A = 2, then evaluate sec A . sin A + tan^2A – cosec A. asked Jun 1, 2024 in Trigonometric Ratios of Acute Angles by HarshKumar ( 32.7k points) … WebCorrect option is A) cosA= 1312 ---- ( 1 ) We know, sin 2A+cos 2A=1 ⇒ sin 2A+(1312)2=1 [ From ( 1 ) ] ⇒ sin 2A+ 169144=1 ⇒ sin 2A=1− 169144 ⇒ sin 2A= 169169−144 ⇒ sin …
If tana 5/12 then sin a + cos a .sec a
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Webtan (θ) = 12 5 tan ( θ) = 12 5 Use the definition of tangent to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values. tan(θ) = opposite adjacent tan ( θ) = opposite adjacent Find the hypotenuse of the unit circle triangle. Web12 jan. 2024 · sec A + tan A = a ----(1) As we know, sec 2 A – tan 2 A = 1. ⇒ (sec A – tan A) (sec A + tan A) = 1. ⇒ sec A – tan A = 1/a ----(2) from equation (1) and equation (2) 2 …
WebIf tan A = 3/4, then sin A cos A = 12/25. Prove the following statement. Solution: It is given that. tan A = 3/4 = Perpendicular/ Base. Consider P = 3k and B = 4k. Using the … Websec ( A) = cosec ( B) Solution The correct option is D sec ( A) = cosec ( B) Given, A and B are complementary angles. ⇒ m ∠ A + m ∠ B = 90 ∘ ⇒ A = 90 - B ... ( i) We know that , sin θ = cos 90 - θ Taking reciprocal on both sides we get, ⇒ 1 sin θ = 1 cos 90 - θ ⇒ cos e c θ = s e c 90 - θ Now, replace θ by B ⇒ cos e c B = s e c 90 - B
Web12 jan. 2024 · If tan A + Sin A = m and tan A - sin A = n then m2 - n2 = Q4. The value of 2 + 2 + 2 + 2 cos 8 θ Q5. From the following data the value of θ if cos θ = 0.4457 x° 0' 6' 12' 18' 24' 30' 36' 42' 48' 54' 1' 2' 3' 4' 5' Difference to subtract 63 0.4540 4446 1013 Q6. WebProve that if tanA= 43, then sinAcosA= 2512 Medium Solution Verified by Toppr As sec 2A−tan 2A=1⇒secA=± tan 2A+1 =± 169 +1=± 1625=± 45 ⇒cosA= secA1 =± 54 And sin 2A+cos 2A=1 ⇒sinA=± 1−cos 2A=± 1− 2516 =± 259 =± 53 ⇒sinAcosA= 2512 Was this answer helpful? 0 0 Similar questions TanA=CotB, prove that A+B=90 ∘ Hard View …
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Web2 dec. 2015 · Explanation: Use the trig identity: tan2A = 2tanA 1 − tan2A (1). First, find tanA = sinA cosA. sinA = 3 5 --> sin2A = 9 25 --> cos2A = 1 − 9 25 = 15 25 - --> cosA = ± 4 5. Because A is in Quadrant II, its cos is negative. cosA = − 4 5 tanA = sinA cosA = (3 5)( − 5 4) = − 3 4 Replace value of tan A = -3/4 into identity (1) --> ranchers and farmers renters insuranceWebsec A - tan A = 5, or (1/cos A) - (sin A/cos A) = 5, or 1-sin A = 5 cos A, or 1-sin A = 5 (1-sin^2 A)^0.5, or Square both sides (1-sin A)^2 = 25 (1-sin^2 A) 1 - 2 sin A + sin^2 A = 25 - 25 sin^2 A, or 26sin^2 A - 2 sin A - 24 = 0, or 13 sin^2 A - sin A - 12 = 0. sin A (1) = [+1+ (1+625)^0.5]/26 = [+1+25]/26 = 26/26 = 1 Hence A (1) = 90 deg ranchers at the lakeWeb24 apr. 2024 · = sin (A)cos (-B) + sin (-B)cos (A) = sin (A)cos (B) - sin (B)cos (A) negative sign while sine is an odd function; so sine spits out the negative = (3/5) (12/13) - (5/13) (4/5) = 36/65 - 20/65 = 16/65 = 0.2461538 Alternatively, you get the same answer using inverse trig functions: A = inverse-sine (3/5) = 36.87 ranchers bankWeb23 dec. 2016 · if secA-tanA =10 than sinA =?,cosA =?,secA =? ranchers atv and tractorWebIf tan A = 5/12, find the value of (sin A + cos A) sec A. ← Prev Question Next Question →. 0 votes. 105k views. asked Sep 7, 2024 in Mathematics by Mubarak (32.9k points) If tan … ranchers and farmers mutual insurance texasWebsec A - tan A = 5, or (1/cos A) - (sin A/cos A) = 5, or 1-sin A = 5 cos A, or 1-sin A = 5(1-sin^2 A)^0.5, or Square both sides (1-sin A)^2 = 25(1-sin^2 A) 1 - 2 sin A + sin^2 A = … ranchers and farmers mutual insurance coWeb31 aug. 2013 · Consider, (sinA + cosA) × secA = (sinA + cosA)/cosA = (sinA/cosA + cosA/cosA) = tanA + 1 = (5/12) + 1 [Given tanA = 5/12] = 17/12 Recommend (1) … oversized gray color wall clocks