WebIn the given figure, the value of x (in cm) is : A 4 B 5 C 6 D 8 Easy Solution Verified by Toppr Correct option is B) PQPA= 62.4= 52 PRPB= 83.2= 52 ⇒ PQPA= PRPB ∠APB=∠QPR So, By SAS property ∴ APB∼ QPR ⇒ PQPA= PRPB= QRAB 52= x2⇒x=5cm Solve any question of Triangles with:- Patterns of problems > Was this answer helpful? 0 … Web4 nov. 2024 · In the given figure, the value of x is (a) 4 cm (b) 5 cm (c) 8 cm (d) 3 cm Advertisement Expert-Verified Answer 19 people found it helpful SmritiSami Given: Triangle ABC, right angled at A. AD ⊥ BC, AC = x, DC = 4 cm and BC = 16 cm To find: Value of x Solution: In triangle ADC (right angled at D) Using Pythagoras Theorem: = AC = x and …
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Web3 okt. 2024 · In the given figure, find the value of x in terms of a,b and.c. triangles; cbse; class-10; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered Oct 3, 2024 by Supria (64.2k points) selected Oct 3, 2024 by faiz . … bj\u0027s coffee coupons
Ex 6.3, 1 - Find the value of the unknown x in the following
Web12 mei 2024 · In the given figure, side BC of ΔABC is produced to D. Consider the ΔABC, We know that the exterior angle of a triangle is equal to the sum of its interior opposite angles. ∴ ∠ABC + ∠BAC = ∠ACD = 68 o + x = 130 o = x = 130 o – 68 o = x = 62 o. Also, we know that the sum of all the angles of a triangles is 180 o. ∴ x + y + 68 o = 180 o Web15 sep. 2024 · Given - Digram in picture. Find - Value of x and y. Solution - To find the value of x and y, we need to find the relationship seperately between three terms. Firstly, finding relation between 1001, y and 143. Here, 1001 is product of 143 and 7. Secondly, finding relation between 143, x and 11. Again using given options, we get 143 is product … Web23 mrt. 2024 · Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript Ex 6.3, 1 (i) Find the value of the unknown x in the following diagrams: Given, ∠A = x ∠B = 50° ∠C = 60° We know that, Sum of angles in triangles = 180° ∠A + ∠B + ∠C = 180° x + 50° + 60° = 180° x + 110° = 180° x = 180° − 110° x = 70° dating site crawler